Question

two cars leave the town's 400 kilometers of Pi at the same time travel towards each other. One car a is 16 kilometers per hour less than the other's. if they meet in 2 hours,what is the rate of the slower car?

Answer 1

200 km/h

1) Gathering the data

Car 1: x

Car 2: x-16

time: 2 hours

2) Considering the formula that relates to Speed, Time, and Displacement, we can write assuming their speeds are at a constant rate.

• The speed of Car 1 and Car 2 can be added so that we can plug them into that formula.

,

• We can then write and cross multiply those ratios.

$\begin{gathered} V=\frac{\Delta s}{\Delta t} \\ x\text{ +x-16 =}\frac{400}{2} \\ 2x-16\text{ =}\frac{400}{2} \\ 2(2x\text{ -16)=400} \\ 4x-32=400 \\ 4x=432 \\ x=216 \end{gathered}$

3) Hence, the slower car is at 216 -16 = 200 km/h