The given quadilateral EFGH is a cyclic quadilateral.
The sum of opposite angle of a cyclic quadilateral is 180 degrees.
The value of measure of angle H can be determined as,
[tex]\begin{gathered} \angle F+\angle H=180^{\circ} \\ 49^{\circ}+\angle H=180^{\circ} \\ \angle H=131^{\circ} \end{gathered}[/tex]Thus, option (F) is the correct solution.
