Question

A set of 3 consecutive integers sums to –138. What is the value of the greatest integer?

Answer 1

we can write the situation mathematically like follows:

$n+(n+1)+(n+2)=-138$

where n is the smallest integer and n+2 is the greatest, let's find first the smallest to find the greatest then.

$n+(n+1)+(n+2)=3n+3$

then

$3n+3=-138$$3n=-141$$n=-\frac{141}{3}=-47$

then the smallest integer will be n=-47 and the greatest will be n+2=-47+2=-45 then the final answe is -45.