Question

What is the molarity of a solution with 18.10 grams of solute and a volume of 1890.0 mL? The solute has a molar mass of 237.8 g/mol.

Answer 1

1) Molarity equation

$M=\frac{\text{number of moles}}{\text{liters of solution}}$

M= Molarity

2) Converting grams (g) into moles (mol)

$\text{moles}=18.10g\cdot\frac{1\text{ mol}}{237.8g}=0.07611\text{ mol}$

3) Converting mL into L

$L=1890.0mL\cdot\frac{1L}{1000mL}=1.890L$

4) Plug in quantities

$M=\frac{0.07611mol}{1.89L}=0.04027M$

The molarity of the solution is 0.04027M.