[tex]\begin{gathered} 2(x-2)^2=8(7+y) \\ 2(x-2)^2=56+8y \\ Steps\text{ to find the inverse} \\ 1.\text{ Exchange position of x and y} \\ 2(y-2)^2=56+8x \\ 2.\text{ Solve y} \\ (y-2)^2=\frac{1}{2}(56+8x) \\ \\ (y-2)^2=28+4x \\ \sqrt[]{(y-2)^2}=\sqrt[]{28+4x} \\ y-2=\pm\sqrt[]{28+4x} \\ y=2\pm\sqrt[]{28+4x} \\ \\ \text{the equation inverse is }y=2\pm\sqrt[]{28+4x} \end{gathered}[/tex]
