Four times the sum of a number and 2/3 can be written in the following way:
[tex]4(x+\frac{2}{3})[/tex]since this expression is equal to 16/3, we can solve for x then:
[tex]\begin{gathered} 4(x+\frac{2}{3})=\frac{16}{3} \\ \Rightarrow4x+\frac{8}{3}=\frac{16}{3} \\ \Rightarrow4x=\frac{16}{3}-\frac{8}{3}=\frac{8}{3} \\ \Rightarrow x=\frac{\frac{8}{3}}{4}=\frac{8}{3\cdot4}=\frac{8}{12}=\frac{2}{3} \\ x=\frac{2}{3} \end{gathered}[/tex]therefore, the missing number is 2/3
