We will have the following:
*We will determine the solution by replacing the pairs of values and calculating, that is:
*a. (-10, 6.5):
[tex]\begin{cases}2(-10)+4(6.5)=6 \\ (-10)-2(6.5)=7\end{cases}\Rightarrow\begin{cases}6=6 \\ -23\ne7\end{cases}[/tex]*b. (-2, 2.5):
[tex]\begin{cases}2(-2)+4(2.5)=6 \\ (-2)-2(2.5)=7\end{cases}\Rightarrow\begin{cases}6=6 \\ -7\ne7\end{cases}[/tex]*c. (5, -1):
[tex]\begin{cases}2(5)+4(-1)=6 \\ (5)-2(-1)=7\end{cases}\Rightarrow\begin{cases}6=6 \\ 7=7\end{cases}[/tex]So, the solution for the system is the point (5, -1).