Question

17. ELECTRICITY The total impedance of a series circuit is the sum of theimpedances of all parts of the circuit. A technician determined that theimpedance of the first part of a particular circuit was 2 + 5j ohms. Theimpedance of the remaining part of the circuit was 3 - 2j ohms. What was the total impedance of the circuit?

Answer 1

Solution

Step 1

Impedance of the first part of the circuit = 2 + 5j

Step 2

Impedance of the second part of the circuit = 3 - 2j

Step 3

$\begin{gathered} Total\text{ impedance = 2 + 5j + 3 - 2j} \\ =\text{ 5 + 3j ohms} \end{gathered}$

Final answer

First option

5 + 3j ohms