Solve
[tex]\begin{gathered} 6x^2-x<\: 2 \\ 6x^2-x-2<0 \end{gathered}[/tex]
Factor
[tex]\begin{gathered} (2x+1)(3x-2)<0 \\ \text{then} \\ 2x+1<0 \\ 2x+1-1<0-1 \\ 2x<-1 \\ \frac{2x}{2}<-\frac{1}{2} \\ x<-\frac{1}{2} \end{gathered}[/tex]
and
[tex]\begin{gathered} 3x-2<0 \\ 3x-2+2<0+2 \\ 3x<2 \\ \frac{3x}{3}<\frac{2}{3} \\ x<\frac{2}{3} \end{gathered}[/tex]
Therefore, Identify the intervals:
[tex]-\frac{1}{2}
Answer: Answer on a number line
Answer in interval notation
[tex](-\frac{1}{2},\frac{2}{3})[/tex]
