Question

4. Bus A travels 600 miles from Portland to San Franciso at an average rate of 50 mph. Bus Bmakes the same trip traveling at an average rate of 60 mph and makes a two hour stop alongthe way. If both busses leave Portland at the same time, which one will be first to arrive inSan Francisco?Answer

Answer 1

Ok, so

Remember the following equation:

$S=\frac{D}{T}$

Speed = (Distance) / (Time)

As we know, Bus A travels 600 miles from Portland to San Franciso at an average rate of 50 mph. So the time it takes it to arrive will be:

$T=\frac{D}{S}=\frac{600\text{miles}}{50\text{mph}}=12h$

Bus B makes the same trip traveling at an average rate of 60 mph and makes a two hour stop along the way.

So,

$T=\frac{D}{S}=\frac{600\text{miles}}{60\text{mph}}=10h$

As it makes a two hour stop along the way, the total time to arrive of the bus B, will be 12h too.

So, both buses arrive at the same time.