A 4.0 kg mass is attached to one end of a rope 2 m long. If the mass is swung in a vertical circle from the free end of the rope, what is the tension in the rope whenthe mass is at its highest point if it is moving with a speed of 5 m/s?

Respuesta :

In order to determine the tension of the rope, consider that the tension is equal to the centripetal

T = Fc - mg

Take into account that the centripetal force is given by the following formula:

Fc = 1/2·mv²/r

where

m: mass = 4.0 kg

v: speed of the mass = 5 m/s

r: radius of the circular trayectory decribes by the mass = 2 m

Look that the radius of the trayectory is equal to the length of the rope.

Replace the values of the parameters into the formula for Fc:

Fc = 1/2·(4.0 kg)(5 m/s)²/(2 m)

Fc = 25 N

The weight of the mass is:

mg = (4.0 kg)(9.8 m/s²) = 39.2 N

Hence, the tension is

T = -14.2N

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