a coast guard looks out from an observation Tower of the height 15m and sees a boat in distress at a distance of 50m what is the angle of depression of the boat from the tower ? round your answer to the nearest tenth
[tex]\text{Let the angle of depression be }\theta[/tex][tex]\begin{gathered} \tan (\theta)=\frac{15}{50}=\frac{3}{10} \\ \Rightarrow\theta=\tan ^{-1}(\frac{3}{10})=16.7degrees \end{gathered}[/tex]
