From the given picture we can see that
A figure formed from
A semicircle with a radius of 3 ft
An isosceles triangle with 2 equal sides of 5 ft
A base equal to the diameter of the semicircle
A height of 4 ft
The rule of the area of the semicircle is
[tex]A_C=\frac{1}{2}\times\pi\times r\times r[/tex]
Pi = 3.14
r = 3
The rule of the area of the triangle is
[tex]A_T=\frac{1}{2}\times base\times height[/tex]
Base = r + r = 3 + 3 = 6
Height = 4
The area of the figure is the sum of them
[tex]\begin{gathered} A=A_C+A_T \\ A=\frac{1}{2}\times3.14\times3\times3+\frac{1}{2}\times6\times4 \\ A=14.13+12 \\ A=26.13\text{ ft}^2 \end{gathered}[/tex]
The area of the figure is 26.13 ft^2
The answer is
A = 26.13 ft^2
