What is the length of the radius of a circle with a center at (2, 3) and passing through (0,4)?а75b/13C✓17d41

A) √5
1) Gathering the data
C(2,3) and point (0,4)
2) Let's write out the formula of the circle:
[tex](x-a)^2+(y-b)^2=r^2[/tex]Now, let's plug into that the Center, and the point (0,4) so that we can find out the radius:
[tex]\begin{gathered} (x-a)^2+(y-b)^2=r^2 \\ (0-2))^2+(4-3))^2=r^2 \\ (0-2)^2+(4-3)^2=r^2 \\ r^2=5 \\ r=\sqrt[]{5} \end{gathered}[/tex]3) Hence, the radius is √5
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