Given:
ABCD is a parallelogram.
Required:
We need to prove
[tex]\text{ AB}\cong\text{CD and BC}\cong\text{DA}[/tex]
Explanation:
We know that alternate interior angles are congruent.
[tex]\angle BCA\cong\angle DAC[/tex][tex]\angle DCA\cong\angle BAC[/tex][tex]AC\cong AC[/tex]
The ASA Postulate. If two angles and the included side of one triangle are congruent to two angles and the included side of a second triangle, then the triangles are congruent.
[tex]\Delta ABC\cong\Delta ACD[/tex]
Reason ASA postulates.
Final answer:
Statements
8)
[tex]\Delta ABC\cong\Delta ACD[/tex]
Reason
8)
ASA postulates