Question

2 Fig. 2.1 shows a hammer being used to drive a nail into a piece of wood.hammer headnailwoodFig. 2.1The mass of the hammer head is 0.15 kg.The speed of the hammer head when it hits the nail is 8.0 m/s.The time for which the hammer head is in contact with the nail is 0.0015 s.The hammer head stops after hitting the nail.1.20(a) Calculate the change in momentum of the hammer head.(b) state the impulse given to nail. (c) calculate the average force between the hammer and the nail

Answer 1

Given:

The mass of the hammerhead is m = 0.15 kg

The speed of the hammerhead is v = 8 m/s

The time for which the hammerhead is in contact with the nail is

$\Delta t\text{ =}0.0015\text{ s}$

To find the change in momentum

The impulse and the average force.

Explanation:

The change in momentum will be

$\begin{gathered} \Delta p\text{ = mv} \\ =\text{ 0.15}\times8 \\ =1.2kg\text{ m/s} \end{gathered}$

The impulse will be

$\begin{gathered} Im\text{pulse = change in momentum} \\ =1.2kg\text{ m/s} \end{gathered}$

The average force will be

$\begin{gathered} F_{av}=\frac{Impulse}{\Delta t} \\ =\frac{1.2}{0.0015} \\ =800\text{ N} \end{gathered}$

Final Answer: The change in momentum is 1.2 kg m/s

The impulse is 1.2 kg m/s.

The average force is 800 N