Question

Solve the following system of equations -16y = 4 4x+ 27y=11 Enter the solution as an ordered pair:(

Answer 1

Given the below equations;

$\begin{gathered} -16y=4 \\ \\ 4x+27y=11 \end{gathered}$

We can solve this by using the substitution method, we'll go ahead and find y in the 1st equation and substitute the value of y into the 2nd equation to find x;

To find y in the 1st equation;

$\begin{gathered} -16y=4 \\ -\frac{16y}{16}=\frac{4}{16} \\ -y=\frac{1}{4} \\ \therefore y=-\frac{1}{4} \end{gathered}$

To find x,let's substitute the value of y into the 2nd equation;

$\begin{gathered} 4x+27(-\frac{1}{4})=11 \\ 4x-\frac{27}{4}=11 \\ 16x-27=44 \\ 16x=44+27 \\ 16x=71 \\ \frac{16x}{16}=\frac{71}{16} \\ x=\frac{71}{16} \\ \end{gathered}$

Therefore, the solution is (71/16, -1/4) or (4.44, 0.25) in decimal.