ANSWER:
The rate of the jet in still air is 802 mph and the speed of the jetstream is 40 mph
STEP-BY-STEP EXPLANATION:
Given:
Let
x = the jet rate at no wind (in mph)
y = the rate of the wind.
Therefore:
[tex]\begin{gathered} \frac{6096}{8}=x-y\rightarrow x=762+y\text{ (1)} \\ \frac{6736}{8}=x+y\rightarrow x=842-y\text{ (2)} \end{gathered}[/tex]We solve the system by means of the matching method, equating both equations like this:
[tex]\begin{gathered} 762+y=842-y \\ 2y=842-762 \\ y=\frac{80}{2} \\ y=40\text{ mph} \\ \\ in\text{ this case of :} \\ x=762+40 \\ x=802\text{ mph} \end{gathered}[/tex]The rate of the jet in still air is 802 mph and the speed of the jetstream is 40 mph.
