A company's marketing department has determined that if their product is sold at the price of p dollars per unit, they can sell q=1000−100p units. Each unit costs 7 dollars to make.

Given:
A company's marketing department has determined that if their product is sold at the price of p dollars per unit, they can sell q=1000−100p units. Each unit costs 7 dollars to make.
Required:
Solve part a and b.
Explanation:
Part A.
[tex]\begin{gathered} Revenue=R=Price\times Quality \\ =pq \\ =1000p-100p^2 \\ \text{ Take the derivative, set equal to zero and solve for p} \\ R^{\prime}=1000-200p \\ 1000-200p=0 \\ 200p=1000 \\ p=5 \end{gathered}[/tex]Part B.
To maximize profits, you need
[tex]\begin{gathered} Profit=Revenue-cost \\ =1000p-100p^2-7(1000-100p) \\ =1700p-100p^2-7000 \\ \text{ Take the derivative, set it equal to zero and solve for p} \\ 1700-200p=0 \\ 200p=1700 \\ p=8.5 \end{gathered}[/tex]Answer:
answered the question.