Question

A ball is kicked at 30 degrees above the horizontal from a cliff of a height of 100 m with a speed v i= 40 m/s. How far from the base of the cliff will the ball hit the ground?

Answer 1

Given:

The angle is

$\theta\text{ = 30}^{\circ}$

The speed of ball is v = 40 m/s

To find the range.

Explanation:

The range of the ball can be calculated as

$\begin{gathered} R=\frac{v^2sin(2\theta)}{g} \\ =\text{ }\frac{(40)^2sin(2\times30)}{9.8} \\ =141.39\text{ m} \end{gathered}$

Thus, the range is 141.39 m