[tex]\begin{gathered} \text{Given y=3}\sqrt[]{9x}\text{ over the domain 0}\leq x\leq9 \\ \text{When x = 0, y=3}\sqrt[]{9(0)} \\ y=3\sqrt[]{0} \\ y=0 \\ \\ \text{ When x = 9} \\ y\text{ = 3}\sqrt[]{9(9)} \\ y=3\sqrt[]{81} \\ y=3(9) \\ y=27 \\ \\ The\text{ range of the function is } \\ 0\text{ }\leq\text{ y}\leq\text{ 27} \end{gathered}[/tex]
The correct option is the first option
