Respuesta :

d)

1) Let's begin with that by finding the probability of picking each drink

We need then to find the sample space, the total number of drinks: 14+28+7=49

The probability of picking water is found by:

[tex]P=\frac{14}{49}=\frac{2}{7}=0.2857[/tex]

The probability of picking cola is then:

[tex]P(cola)=\frac{28}{49}=\frac{4}{7}=0.5714[/tex]

And the probability of picking Lemonade is:

[tex]P(lemonade)=\frac{7}{49}=\frac{1}{7}=0.1428[/tex]

2) Now, let's analyze the statements:

a) You are twice as likely to select cola than water:

Let's divide these probabilities and check:

[tex]\frac{P(cola)}{P(water)}=\frac{\frac{4}{7}}{\frac{2}{7}}=\frac{4}{7}\cdot\frac{7}{2}=2[/tex]

True

b)

[tex]\frac{P(lemonade)}{P(water)}=\frac{\frac{1}{7}}{\frac{2}{7}}=\frac{1}{7}\times\frac{7}{2}=\frac{1}{2}[/tex]

True

c) We can compare the probabilities in their decimal form:

[tex]P(cola)=0.5714,P(water)=0.2857,P(lemonade)=0.1428[/tex]

True

d)

[tex]\begin{gathered} P(water)=0.28 \\ P(cola)=0.57 \end{gathered}[/tex]

False

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