Help with number four a-d is all of number four

d)
1) Let's begin with that by finding the probability of picking each drink
We need then to find the sample space, the total number of drinks: 14+28+7=49
The probability of picking water is found by:
[tex]P=\frac{14}{49}=\frac{2}{7}=0.2857[/tex]The probability of picking cola is then:
[tex]P(cola)=\frac{28}{49}=\frac{4}{7}=0.5714[/tex]And the probability of picking Lemonade is:
[tex]P(lemonade)=\frac{7}{49}=\frac{1}{7}=0.1428[/tex]2) Now, let's analyze the statements:
a) You are twice as likely to select cola than water:
Let's divide these probabilities and check:
[tex]\frac{P(cola)}{P(water)}=\frac{\frac{4}{7}}{\frac{2}{7}}=\frac{4}{7}\cdot\frac{7}{2}=2[/tex]True
b)
[tex]\frac{P(lemonade)}{P(water)}=\frac{\frac{1}{7}}{\frac{2}{7}}=\frac{1}{7}\times\frac{7}{2}=\frac{1}{2}[/tex]True
c) We can compare the probabilities in their decimal form:
[tex]P(cola)=0.5714,P(water)=0.2857,P(lemonade)=0.1428[/tex]True
d)
[tex]\begin{gathered} P(water)=0.28 \\ P(cola)=0.57 \end{gathered}[/tex]False