Solution
Given
[tex]\begin{gathered} (x+7)^2=16 \\ \\ \text{ Taking the square root of both sides} \\ \Rightarrow(x+7)=\pm\sqrt{16} \\ \\ \Rightarrow(x+7)=\pm4 \\ \\ \Rightarrow x=-7\pm4 \\ \\ \Rightarrow x=-7-4,-7+4 \\ \\ \Rightarrow x=-11,-3 \end{gathered}[/tex]Answer(s): -11, -3