[tex]\begin{gathered} y<2x-3 \\ y>-x+1 \\ thus,2x-3\text{ }>-x+1 \\ 2x+x>\text{ 1+3} \\ 3x>4 \\ x>\frac{4}{3} \\ y\text{ }<\text{ 2(}\frac{4}{3})-3 \\ y<\text{ }\frac{8}{3}-3,\text{ y}<-\frac{1}{3} \\ \text{therefore, x}>\frac{4}{3},\text{ y}<\text{ -}\frac{1}{3} \end{gathered}[/tex]
