Question

A big box store employee pulls a pallet a distance of 15 meters to a new location in the store. The angle of the handle is about 35 degrees above the floor and the worker applies a forces of 45 N along the handle. On the newly polished floor, friction between the wheels and the floor is 25N. What is the work done by the employee on the pallet.

Answer 1

Given .

The distance travelled is s=15 m

The angle of the handle is

$\theta=35^o$

The force applied is F=45 N.

The frictional force is f=25 N

The horizontal force is

F'=45cos35=36.86 N.

Thus the net force is:

$F_{net}=F^{\prime}-f=36.86-25=11.86N$

Thus the work done is:

$W=F_{net}.s=11.86\times15=177.9J$

Thus the answer is 177.9J