PLEASE HELP I DONT UNDERSTAND THESE THAT WELL. All you have to do is get them to add up to 80 equally on both sides like a balance scale and can’t use same number twice

Solution:
It is divided 40 each on both sides
Let a represent heart
Let b represent triangle
Let c represent flower
For the right side;
There are 5 hearts, i.e.
[tex]\begin{gathered} 5a=40 \\ a=\frac{40}{5} \\ a=8 \end{gathered}[/tex]For the left side;
[tex]\begin{gathered} 2b+c+a+4c=40 \\ Where\text{ a}=8 \\ 2b+5c+8=40 \\ 2b+5c=40-8 \\ 2b+5c=32...(1) \\ And \\ 2b+c=4c \\ 2b=4c-c \\ 2b=3c...(2) \end{gathered}[/tex]Substitute 3c for 2b into equation (1)
[tex]\begin{gathered} 2b+5c=32 \\ 3c+5c=32 \\ 8c=32 \\ c=\frac{32}{8} \\ c=4 \\ Substitute\text{ 4 for c into equation} \\ 2b=3c \\ 2b=3(4) \\ 2b=12 \\ b=\frac{12}{2} \\ b=6 \end{gathered}[/tex]Hence, the answer is
[tex]\begin{gathered} heart=a=8 \\ triangle=b=6 \\ flower=c=4 \end{gathered}[/tex]