Given:
[tex]7(\sqrt[3]{2x})-3(\sqrt[3]{16x})-3(\sqrt[3]{8x})[/tex]
Simplify the expression,
[tex]\begin{gathered} 7\mleft(\sqrt[3]{2x}\mright)-3\mleft(\sqrt[3]{16x}\mright)-3\mleft(\sqrt[3]{8x}\mright) \\ =7\mleft(\sqrt[3]{2x}\mright)-3\mleft(\sqrt[3]{2\cdot2^3x}\mright)-3\mleft(\sqrt[3]{2^3x}\mright) \\ We\text{ know that, }\sqrt[3]{2^3}=2 \\ =7(\sqrt[3]{2x})-3\cdot2(\sqrt[3]{2x})-3\cdot2(\sqrt[3]{x}) \\ =7(\sqrt[3]{2x})-6(\sqrt[3]{2x})-6(\sqrt[3]{x}) \\ =\sqrt[3]{2x}-6\sqrt[3]{x} \end{gathered}[/tex]
Answer: opti
