SOLUTION
Step 1:
We are to find the 7th term of the sequence whose first term is 5 and common difference is 2.
Step 2:
We make use of this formula;
[tex]T_n\text{ = a + (n-1)d}[/tex]Where a is the first term, n is the number of terms and d is the common difference.
Step 3:
So, a = 5, d = 2 and n = 7
[tex]\begin{gathered} T_n\text{ = a + (n - 1)d} \\ T_7\text{ = 5 + (7-1) 2} \\ T_7_{}\text{ = 5 + 2(6)} \\ T_7\text{ = 5 + 12} \\ T_7\text{ = 17} \end{gathered}[/tex]CONCLUSION:
The 7th term of the sequence whose first term is 5 and each term is found by adding 2 to the previous term is 17.