Question

Find the mass of the meter stick (100 cm). For this problem you do not have to convert the grams to kilograms ornewtons.Remember:Only respond with a numerical answer. No units are required.

Answer 1

The center of the stick from the left edge of the stick is at,

$\begin{gathered} d=\frac{100}{2} \\ d=50\text{ cm} \end{gathered}$

The mass 125 g is at the distance of 25 cm from the hanging.

Thus, the distance of center of the stick from the hanging is,

$\begin{gathered} d^{\prime}=50-25 \\ d^{\prime}=25\text{ cm} \end{gathered}$

As the stick is balanced,

Thus, the net moment due to the mass of the stick and given 125 g mass is zero.

$125\times g\times25-m\times g\times25=0$

where g is the acceleration due to gravity,

Substituting the known values,

$\begin{gathered} 125\times9.8\times25-m\times9.8\times25=0 \\ (125-m)\times9.8\times25=0 \\ (125-m)=0 \\ m=125\text{ g} \end{gathered}$

Thus, the mass of the stick is 125 grams.

In the terms of kilogram, the value of the mass is,

$\begin{gathered} m=125\times10^{-3}\text{ kg} \\ m=0.125\text{ kg} \end{gathered}$

The value of the mass in newton is,

$\begin{gathered} W=m\times g \\ W=0.125\times9.8 \\ W=1.225\text{ N} \end{gathered}$

Thus, the value of the weight of the stick is 1.225 N.