Given
Mass of water, m= 200g
Change in temperature,
[tex]T=85^oC-10^oC=75^oC[/tex]To find
Heat required
Explanation
We know specific heat of water is
[tex]c=\frac{4.18J}{g^oC}[/tex]Thus heat required is
[tex]\begin{gathered} Q=mcT \\ \Rightarrow Q=200\times4.18\times75 \\ \Rightarrow Q=62700J \end{gathered}[/tex]Conclusion
The heat necessary is 62700 J