The dimensions that we must use in this problem, are the dimensions of the screen of a TV of 75 inches:
• W = width = 65.4" ,
,• H = heigh = 36.8".
• The form of the TV is a rectangle, we compute the area A of the rectangle by the following formula:
[tex]A=W\cdot H=65.4in\cdot36.8in=2406.72in^2.[/tex]• The aspect ratio r is given by the quotient of the width (W) by the height (H):
[tex]r=\frac{W}{H}=\frac{65.4in}{36.8in}=1.777.[/tex]• The length of the TV diagonal L can be computed using Pitagoras Theorem:
[tex]L=\sqrt[]{W^2+H^2}=\sqrt[]{(65.4in)^2+(36.8in)^2}\cong75.04in.[/tex]Answer
• width = 65.4",
,• heigh = 36.8",
,• area = 2406.72in²,
,• aspect ratio = 1.777
,• length of the diagonal = 75.04in.
