Question

For the arithmetic sequence –17, -7,3, 13,..., find a 35оа-321.Ob323ос-323Od289

Answer 1

We have the next sequence

-17,-7,3,13

first we need to find the difference between each value

-17+d=-7

d=17-7

d=10

then we have the next formula in order to find any number in the sequence

$a_n=a_1+d(n-1)$

in our case

n=35

a1=-17

therefore for a35

$a_{35}=-17+10(35-1)$$a_{35}=323$

therefore the answer is 323