Respuesta :

We are given the following function:

[tex]y=x^3-9x[/tex]

We are asked to determine the derivative. To do that we will take the derivative to both sides:

[tex]\frac{dy}{dx}=\frac{d}{dx}(x^3-9x)[/tex]

Now, we distribute the derivative:

[tex]\frac{dy}{dx}=\frac{d}{dx}(x^3)-\frac{d}{dx}(9x)[/tex]

For the first derivative we use the following rule:

[tex]\frac{d(x^n)}{dx}=nx^{n-1}[/tex]

Applying the property we get:

[tex]\frac{dy}{dx}=3x^2-\frac{d}{dx}(9x)[/tex]

Now, we use the following rule for the final derivative:

[tex]\frac{d}{dx}(ax)=a[/tex]

Applying the rule we get:

[tex]\frac{dy}{dx}=3x^2-9[/tex]

Since we can't simplify it any further this is the derivative.

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