We have the following:
[tex]x+\frac{1}{-2}=-2x+\frac{3}{4\text{ }}[/tex]solving for x:
[tex]\begin{gathered} x+\frac{1}{-2}=-2x+\frac{3}{4} \\ x-\frac{1}{2}+\frac{1}{2}=-2x+\frac{3}{4}+\frac{1}{2} \\ x=-2x+\frac{5}{4} \\ x+2x=-2x+\frac{5}{4}+2x \\ 3x=\frac{5}{4} \\ 3x\cdot\frac{1}{3}=\frac{5}{4}\cdot\frac{1}{3} \\ x=\frac{5}{12} \end{gathered}[/tex]the answer is x equal 5/12
