From the graph we notice that the trend line passes through the points (3,2) and (10,5) and we know that the equation of a line is given by:
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
Plugging the values of the points we found we have:
[tex]\begin{gathered} y-2=\frac{5-2}{10-3}(x-3) \\ y-2=\frac{3}{7}(x-3) \\ y-2=\frac{3}{7}x-\frac{9}{7} \\ y=\frac{3}{7}x-\frac{9}{7}+2 \\ y=\frac{3}{7}x+\frac{5}{7} \\ y=0.42x+0.7 \end{gathered}[/tex]
Renaming variable y as g(x) we have that:
[tex]g(x)=0.42x+0.7[/tex]
