Given that a printer creates a right triangular card where the hypotenuse, h, Is three times as long as the shorter leg. We are asked to find the length of the longer leg. This can be seen below.
Explanation
Let the of the shorter leg be h. This implies that the length of the hypotenuse is
[tex]\text{Hypotenuse = 3 x h =3h}[/tex]
Also, let the longer leg be l. Recall the Pythagoras theorem below;
[tex]\text{Hypotenuse}^2=(Longer\text{ leg)}^2+(\text{Shorter leg)}^2[/tex]
We can then insert the assumed parameters into the above
[tex]\begin{gathered} l^2+h^2=(3h)^2 \\ l^2+h^2=9h^2^{} \\ l^2=9h^2-h^2 \\ l^2=8h^2 \\ l=\sqrt[]{8h^2} \\ l=2\sqrt[]{2}h \end{gathered}[/tex]
Therefore, by comparison
Answer:
[tex]a=2;b=2;c=1[/tex]