Question

Lines PQ and RS are perpendicular. Find x. P(1, -2); Q(3, 6); R(x, 6); S(6, 5)x = ?

Answer 1

Is valid

m1 • m2 = -1

then

m1= Y/X = ( 6 - - 2)/ (3-1) = 8/2= 4

m2= Y/X = (5 - 6)/(6 - x) = -1/( 6-x)

Now find x, replace

4• (-1/(6-x)) = -1

then

-4 = - (6-x)

-4 = -6 + x

-4+6= 2= x

Then answer is , x= 2