Question

(AWARDING BRAINLIEST!)Points P, Q, and R are collinear on PR, and PQ:PR = . P islocated at the origin, Q is located at (x, y), and R islocated at (-12,0). What are the values of x and y?

Answer 1

Explanation:

We can model the situation as:

Since P and R have a y-coordinate equal to 0, Q has a y-coordinate 0

Now, to calculate the x-coordinate, we can formulate the following equations:

Rx - Px = 3a

Qx - Px = 2a

Where Rx is the x-coordinate of R, Px is the x-coordinate of P and Qx is the x-coordinate of Q. So, replacing the values:

-12 - 0 = 3a

x - 0 = 2a

Now, solving for a, we get:

-12 - 0 = 3a

-12 = 3a

-12/3 = a

-4 = a

Replacing on the second equation, we get:

x - 0 = 2a

x = 2a

x = 2*(-4)

x = -8

Therefore, the coordinates of Q are (-8, 0)

Answer: (-8, 0)