The scale is:
[tex]\frac{1}{4}inch=2\text{ fe}et[/tex]This means that every 1/4 inch in the scale model represents 2 feet of the real plane.
The real length of the plane is:
[tex]40\text{ ft}[/tex]To solve this problem is useful to take the scale:
[tex]\frac{1}{4}inch=2\text{ fe}et[/tex]And find how many inches represent just 1 foot. We can find this by dividing both sides by 2:
[tex]\frac{1}{8}\text{inch}=1\text{feet}[/tex]Now that we know that 1 foot represents 1/8 inches, the last step is to multiply 40 feet by 1/8 and we will find the length of the plane in the scale model:
[tex]40\times\frac{1}{8}\text{inch}=\frac{40}{8}\text{inch}=5\text{inch}[/tex]Answer: the length in the scale model is 5 inches.