die tossed 1000 times
die goes through numbers 1 - 6
2 - 4 - 6
2 - 4 - 6 is all even numbers
Which means they're three different sides the die can land on to give a even number
If the die was tossed 1000 times, in order to find how many times the die would land on even numbers we have to...
3 / 6 × 1000
3 = the number of sides it could land on
6 = total sides
1000 = how many times the die was rolled
[tex]\frac{3}{6}\times1000=3\div6=0.5\times1000=500[/tex]
Which means the number of times the die would land on a even number would be able 500 times or option C.
