Question

Find a polynomial f(x) of degree 3 that has the following zeros.8 (multiplicity 2), -2Leave your answer in factored form.

Answer 1

Step 1: Given data and concept

$\begin{gathered} \text{Zeros are:} \\ \text{x = -2 === (x + 2) is a factor} \\ 8(mu\text{ltiplicity }2)======(x-8)^2 \end{gathered}$

Step 2: You will write the function f(x) of degree three in a factored form.

$\begin{gathered} \text{Therefore f(x) is a multiply of all the factors.} \\ f(x)=(x+2)(x-8)^2 \end{gathered}$

Step 3: Final answer

$f(x)=(x+2)(x-8)^2$

f(x) = (x + 2)(x - 8)²