Question

The sum of three consecutive odd integers is 333.Find 3 integers

Answer 1

A seed for odd numbers is:

$(2n+1)$

This means that if you change n for any number you like, you'll always get an odd number.

Now, odd numbers are 2 places away from each other. This way, the seeds for three consecutive odd numbers will be:

$\begin{gathered} (2n+1) \\ (2n+3) \\ (2n+5) \end{gathered}$

Now, this numbers add up to 333. Therefore,

$(2n+1)+(2n+3)+(2n+5)=333$

Solving for n,

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