Given:
[tex]2m+2m\ne4m^2[/tex]Required:
We need to fin\gt\ht the value of m that proves that 2m + 2m is not equivalent to 4m^2.
Explanation:
[tex]2m+2m\ne4m^2[/tex][tex]4m\ne4m^2[/tex]Substitute m =0 in the equation.
[tex]4(0)\ne4(0)^2[/tex][tex]0\ne0[/tex]This is not true.
So m =0 does not prove that 2m + 2m is not equivalent to 4m^2
Substitute m =1 in the equaiton.
[tex]4(1)\ne4(1)^2[/tex][tex]4\ne4[/tex]This is not true.
So m =1 does not prove that 2m + 2m is not equivalent to 4m^2
Substitute m =2 in the equaiton.
[tex]4(2)\ne4(2)^2[/tex][tex]8\ne16[/tex]This is true.
So m =2 proves that 2m + 2m is not equivalent to 4m^2
Final answer:
[tex]m=2[/tex]