We are given the following two functions
[tex]\begin{gathered} f(x)=x^2-8x+12 \\ g(x)=-6_{} \end{gathered}[/tex]We are to find (f/g)(x)
(f/g)(x) is basically the division of function f(x) by function g(x)
[tex](\frac{f}{g})(x)=\frac{f(x)}{g(x)}=\frac{x^2-8x+12}{-6}=\frac{x^2}{-6}-\frac{8x}{-6}+\frac{12}{-6}=-\frac{1}{6}x^2+\frac{2}{3}x-2[/tex]Therefore, the function (f/g)(x) is
[tex](\frac{f}{g})(x)=-\frac{1}{6}x^2+\frac{2}{3}x-2[/tex]