Respuesta :

We are given the following two functions

[tex]\begin{gathered} f(x)=x^2-8x+12 \\ g(x)=-6_{} \end{gathered}[/tex]

We are to find (f/g)(x)

(f/g)(x) is basically the division of function f(x) by function g(x)

[tex](\frac{f}{g})(x)=\frac{f(x)}{g(x)}=\frac{x^2-8x+12}{-6}=\frac{x^2}{-6}-\frac{8x}{-6}+\frac{12}{-6}=-\frac{1}{6}x^2+\frac{2}{3}x-2[/tex]

Therefore, the function (f/g)(x) is

[tex](\frac{f}{g})(x)=-\frac{1}{6}x^2+\frac{2}{3}x-2[/tex]

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