If np >= 5 and nq >= 5 , estimate P(at least 10) with n = 13 and p = 0.5 by using the normal distribution as an approximation to the binomial distribution ; if np < 5 or nq < 5 then state that the normal approximation is not suitable.

If np gt 5 and nq gt 5 estimate Pat least 10 with n 13 and p 05 by using the normal distribution as an approximation to the binomial distribution if np lt 5 or class=

Respuesta :

The question provides that:

[tex]\begin{gathered} n=13 \\ p=0.5 \end{gathered}[/tex]

Therefore, we have that:

[tex]q=1-p=1-0.5=0.5[/tex]

To check if we can use the normal distribution as an approximation, we will check the values of np and nq:

[tex]\begin{gathered} np=13\times0.5=6.5 \\ nq=13\times0.5=6.5 \end{gathered}[/tex]

Since,

[tex]\begin{gathered} np\ge5 \\ \text{and} \\ nq\ge5 \end{gathered}[/tex]

then we can use the normal distribution as an approximation.

To evaluate P (at least 10), we are evaluating:

[tex]P(X\ge10)[/tex]

The standard deviation of the distribution is gotten to be:

[tex]\sigma=\sqrt[]{np}=\sqrt[]{6.5}=2.550[/tex]

The mean is 6.5.

Therefore, the Z-score is gotten to be:

[tex]Z=\frac{x-\bar{x}}{\sigma}[/tex]

Hence, it is calculated to be:

[tex]Z=\frac{10-6.5}{2.550}=1.37[/tex]

The probability is therefore given to be:

[tex]P(Z\ge1.37)=Pr(0\le Z)-Pr(0\le Z\le1.37)[/tex]

Using the Probability Distribution Table, we have:

[tex]P(Z\ge1.37)=0.5-0.4147=0.0853\approx0.085[/tex]

Therefore, the answer is:

[tex]P(at\text{ }least\text{ }10)=0.085[/tex]

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