Question

Which of these could be the value of x in the triangke below?EXPLAIN

Answer 1

using sin rule

$\begin{gathered} \frac{22}{\sin50}=\frac{4x}{\sin 43} \\ 22\sin 43=4x\sin 50 \\ 4x=\frac{22\sin 43}{\sin 50} \\ 4x=\frac{15.0039639214}{0.76604444311} \\ 4x=19.5862838721 \\ x=\frac{19.5862838721}{4} \\ x=4.89657096803 \\ x\approx5 \end{gathered}$