Answer:
(a)10x+5y=50
(b)4 $5 bills
(c)3 $10 bills
Explanation:
Part A
Given:
The number of $10 bills = x
The number of $5 bills = y
If the total amount of money in his wallet is $50, then:
[tex]10x+5y=50\ldots(1)[/tex]
Part B
If the number of $10 bills, x = 3
From the equation above:
[tex]\begin{gathered} 10x+5y=50 \\ 10(3)+5y=50 \\ 30+5y=50 \\ 5y=50-30 \\ 5y=20 \\ y=\frac{20}{5} \\ y=4 \end{gathered}[/tex]
Therefore, if there are 3 $10 bills, there are 4 $5 bills.
Part C
If the number of $5 bills, y=6, then:
[tex]\begin{gathered} 10x+5y=60 \\ 10x+5(6)=60 \\ 10x=60-30 \\ 10x=30 \\ x=\frac{30}{10} \\ x=3 \end{gathered}[/tex]
Therefore, if there are 6 $5 bills, there are 3 $10 bills.