Question

<1 and <2 are complementary angles. Find:a) m<1 b) m<2c) m<3

Answer 1

Problem

Solution

For this case we know that <1 and z2 are complementary and that means:

m<1 +m <2 =90º

From the figure we can see that :

m<1 +142=180º

m<1 = 180-142= 38º

Then we can find the value for m<2 on this way:

m<2 = 90 -38º= 52º

And finally since angle 2 and 3 are opposed by the vertex then we can conclude that:

m<3 = m<2 = 52º