Answer:
The correct answer choices are;
[tex]\begin{gathered} 3\text{ cans of paint will cover 60\% of Dalia's room} \\ \text{Dalia's entire room requires 5 cans of paint.} \end{gathered}[/tex]
Explanation:
Given that one-half of a can of paint can cover one-tenth of Dalia's room.
[tex]\begin{gathered} \frac{1}{2}\text{ can }\rightarrow\text{ }\frac{1}{10}\text{ }of\text{ her room} \\ mu\text{ltiplying through by 2;} \\ \frac{1}{2}\times2\text{ can }\rightarrow\text{ }\frac{1}{10}\times2\text{ }of\text{ her room} \\ 1\text{ can }\rightarrow\text{ }\frac{1}{5}\text{ }of\text{ her room} \end{gathered}[/tex]
So;
[tex]\text{Each can of paint will cover }\frac{1}{5}\text{ of Dalia's room}[/tex]
Also;
[tex]\begin{gathered} \frac{1}{2}\text{ can }\rightarrow\text{ }\frac{1}{10}\text{ }of\text{ her room} \\ \text{ multiply through by 6;} \\ \frac{1}{2}\times6\text{ can }\rightarrow\text{ }\frac{1}{10}\times6\text{ }of\text{ her room} \\ 3\text{ can }\rightarrow\text{ }\frac{6}{10}\text{ }of\text{ her room} \\ 3\text{ can }\rightarrow\text{ 60\% }of\text{ her room} \end{gathered}[/tex]
So,
[tex]3\text{ cans of paint will cover 60\% of Dalia's room}[/tex]
To cover the whole room;
[tex]\begin{gathered} \frac{1}{2}\text{ can }\rightarrow\text{ }\frac{1}{10}\text{ }of\text{ her room} \\ \text{ multiply both sides by 10;} \\ \frac{10}{2}\text{ can }\rightarrow\text{ }\frac{10}{10}\text{ }of\text{ her room} \\ 5\text{ can }\rightarrow\text{ the whole }of\text{ her room} \end{gathered}[/tex]
Therefore, the correct answer choices are;
[tex]\begin{gathered} 3\text{ cans of paint will cover 60\% of Dalia's room} \\ \text{Dalia's entire room requires 5 cans of paint.} \end{gathered}[/tex]