Question

Consider the following quadratic function. Y=x^2-2x+3Graph this quadratic function by identifying two points on the parabola, other than the vertex and zeros.Your answer must be between -10 and 10.

Answer 1

We can find two points different than the vertex and zero by giving some values to the variable x. For instance, if we choose the value x=1, we have

$y=1^2-2(1)+3$

which gives

$\begin{gathered} y=1-2+3 \\ y=2 \end{gathered}$

so we have obtained the point

$A=(1,2)$

Similarly, we can substitute the value x=2 and get

$\begin{gathered} y=2^2-2(2)+3 \\ \text{then} \\ y=4-4+3 \\ y=3 \end{gathered}$

then, we have obtained the point

$B=(2,3)$

Then, the graph is